4z^2+20z+25=0

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Solution for 4z^2+20z+25=0 equation: 



4z^2+20z+25=0

a = 4; b = 20; c = +25;
Δ = b2-4ac
Δ = 202-4·4·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{-20}{8}=-2+1/2$

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